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In how many possible wasy can write 3240 as a product of 3 positive integers a,b and c. Option a) 450 b)420 c)350 d)320
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From MSIT
probability
asked
Jul 28, 2014
in
TCS
by
raviteja
edited
Jul 29, 2014
by
raviteja
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1 Answer
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3240=2^3*3^4*5
we have to distribute three 2 to three numbers : 3+3-1C3-1=5C2=10
similarly for 3 and 5
therefore total=10*15*3=450
answered
Sep 26, 2015
by
anita kori
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