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sum of the digits of 5^2010*8^673

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asked Jul 25, 2014 in TCS by Campusgate

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Best answer
${5^{2010}} \times {8^{673}} = {5^{2010}} \times {({2^3})^{673}} = {5^{2010}} \times {2^{2019}}$
$ \Rightarrow {(5 \times 2)^{2010}} \times {2^9} = {10^{2010}} \times 512 = 512\underbrace {00........0}_\text{2010 zeroes}$
$\Rightarrow$ Sum of the digits = 5 + 1 + 2 = 8
answered Jul 25, 2014 by Campusgate
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