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Arun makes a popular brand of ice cream in a rectangular shaped bar 6cm long, 5cm wide and 2cm thick. To cut costs, the company had decided to reduce the volume of the bar by 19%. The thickness will remain same, but the length and width will be decreased by some percentage. The new width will be,

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asked Oct 29, 2013 in TCS by Campusgate
retagged Oct 30, 2013 by Campusgate

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Volume =$l \times b \times h$ = $6 \times 5 \times 2$  = 60 $c{m^3}$
Now volume is reduced by 19%.
Therefore, new volume = $\displaystyle\frac{{(100 - 19)}}{{100}} \times 60 = 48.6$
Now, thickness remains same and let length and breadth be reduced to x%
so, new volume: $\left( {\displaystyle\frac{x}{{100}} \times 6} \right)\left( {\displaystyle\frac{x}{{100}} \times 5} \right)2 = 48.6$
Solving we get x =90
thus length and width is reduced by 10%
New width = 5-(10% of 5)=4.5

answered Oct 29, 2013 by Campusgate
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